- Use the below to perform the following tasks:
seq = "CGGTAAGGCACTTGATATATTAATGTTCAGGCGGACATCGGCAGGGTATATTGCGTTAGGATCTAATTAATCTATCAGACTACTTGAGGATTGTCACCTGATGGTAATAGCGTAGTGGGGATCGCTAATCCTACTGTCGATAGACGGCTGCGGTTAAACTAAGCATCTTGCTTCCGGACGGTGGAACCGATTCAAGCGTTAGCAAATGTCAGGTTCACACTAAAGAATCAGCGGGTCTCCCCTACATCTTGAGTTTTATGGCTAACCCTATATCTGTCGATAGCATGGCAGGTTCAATTTAATCACAGTGCTTGCACTGACCTCGCCTACCGGAAGCCCCGCCGCCCAAAGTGACACCAGAGTCTTCGTCACGCAGATAACGCCCCGTGCTATCTGTCCCCCGTCCTTCGAGCAGGAGTTTGGTCTGACGCCTACTTCGGCGAACGTAACCCCTCCTTGTCTGTATTAAACTGCCCCGGATGTCGACTGGTAACAAGACGGACTACAAATAATGTGTACCTTTAGACGTTCTTTAGTGATATATTGTGACCACGTATTACAGAGATACACGACATCTCCTTTATAGGTACACATAACCTAGGATCCGTAGCACCGGGCCGGATTCTGCCCAGCAAGGTGCATCCCATAAGCGTAAACACTGCACGGCGGTCAGAACTCCCCACAATCGATACGGTGTCAACTATGGTACGGATGTCAGTCGGTCCTGTAGATGCACTTGGAAGTGTACCGCGTAGCGTCGCAGGAGCGTAAACATCACCTGGACGGTCCTTTCCAGTAATGAGGAACTCAAACATATAGGGCAGG"- What is the complement of this strand of DNA?
- What is the reverse complement of this strand of DNA?
comp = ["A" if bp=="T" else "T" if bp=="A" else "G" if bp=="C" else "C" for bp in seq] ''.join(comp) comp.reverse() ''.join(comp)OR without list comprehension is a bit cleaner
comp_dict = {"A":"T", "T":"A", "G":"C", "C":"G"} comp = [] for bp in seq: comp.append(comp_dict[bp]) ''.join(comp) comp.reverse() ''.join(comp)OR with if statements instead
comp = [] for bp in seq: if bp == "T": comp.append("A") elif bp == "A": comp.append("T") elif bp == "G": comp.append("C") else: comp.append("G") ''.join(comp) comp.reverse() ''.join(comp)
-
Use the below to perform the following tasks:
table = { 'AUA':'I', 'AUC':'I', 'AUU':'I', 'AUG':'M', 'ACA':'T', 'ACC':'T', 'ACG':'T', 'ACU':'T', 'AAC':'N', 'AAU':'N', 'AAA':'K', 'AAG':'K', 'AGC':'S', 'AGU':'S', 'AGA':'R', 'AGG':'R', 'CUA':'L', 'CUC':'L', 'CUG':'L', 'CUU':'L', 'CCA':'P', 'CCC':'P', 'CCG':'P', 'CCU':'P', 'CAC':'H', 'CAU':'H', 'CAA':'Q', 'CAG':'Q', 'CGA':'R', 'CGC':'R', 'CGG':'R', 'CGU':'R', 'GUA':'V', 'GUC':'V', 'GUG':'V', 'GUU':'V', 'GCA':'A', 'GCC':'A', 'GCG':'A', 'GCU':'A', 'GAC':'D', 'GAU':'D', 'GAA':'E', 'GAG':'E', 'GGA':'G', 'GGC':'G', 'GGG':'G', 'GGU':'G', 'UCA':'S', 'UCC':'S', 'UCG':'S', 'UCU':'S', 'UUC':'F', 'UUU':'F', 'UUA':'L', 'UUG':'L', 'UAC':'Y', 'UAU':'Y', 'UAA':'Stop', 'UAG':'Stop', 'UGC':'C', 'UGU':'C', 'UGA':'Stop', 'UGG':'W', } rna = "AUGAGCGCGAGUCUUGGUCUCGCAUGGCCCGUGGUCGGGACAGCUGCACAUGGGGGACCAGUUAUCCUCAGUAUAACUUUCUGCACCGAGACAAUGACUCAGUUACAGCGUAAUUUCAUUCUCCCUUCGCCAAAUGAUCCCUGGCUAAGUAACCAAAUUAAGCCCAAGCCUUGGACCGGCAGGAGUGAGCUGCUCUUUCAUAGGGGCAAAUCCAGCACGCCGCGGACGUCGAAGCCGUUGAAUCCACCACCGACGGUAUCGGGCUCCGGCAAUACACCAAUAAUUCCCUGCUUAACCCGUCCGUCUACUUCAGCUGUGACCCCAACGCGUGAUGACUGGCUGCGCCACGAGCACCCAGGACUCCGGAACCUUGAGCAUGGAAUGAUAAAAUUGGGCUCAGCCUGCUCAGUUCAAAGGGGCCCUUCAAGCUUACGCCCGAUCAGACAUUACAGCACUUCGAGGGAUCGUAUAAGAGCUUGUCUCCAUAACACGACCCGAUGGGGCCAACAGACACUACUUCGAACUGCCGGGGGUCGAGAAUUAAUUCUACUGACUCCGUCCAGACACUGGGGGUUCCAAACUCAUUGGCUUCUAUGUGCGCCAGAGUCGUGGUGUAGGAUUUUUACUCCAUCUAUGAUGCUCGCUCUAGCACCACGCUUAUCCUACGUUAAAGCGUCAACUUCUGCUCUCACCCGCUUCUAUAGAACCAAUAGGAUGACCUGUUACCUUAAUAUAUUCUGCGCAGGGGGUGAUAAGAGACCGAAGAGAUAUCAGACCCUUUAUCAGACCUUGGCGCCCGCUAGCGCGACAUGUAAUACCCCGAUCGGCCCAAUACAUUCGCCUCCCCACGUGGGCCCUCCCCGUGCCACUCACCCCCACCCCCUGUUAUUACAGCUCCGAUUCUGCUAUUUUACCAUGCUCCAUCCCUUUAGAACAUCCUGGCGAACCAGCUAUUCUGUUCCUCUGGGGACAAGUCACGGAGUUCUCCCCCCGACCCCAGCCGCGUUUGCCCGUAUUACGAUUAGGUAUCGUCGCUUGAUGCUCAUAUGCCACAGGUCCACGAAAAGUCGCCUAUUUCCAAUCAGAGACCCGAAGGCUGUACGUUGGUUUAUGACAAUGAUCUUGAGCAUCGUUUCGAGCGCAGAGACUGGAGAUUUCCCUUGUCUAGACCAGAUGACGGGCGAUACGAUACCCUGGUUCAUGAAUGCAAAACUCGUUUCGACCUUUCUAUGGAGAUCGACUGGAGAAGCGGGCGUAUUCUGUAAAACUCGCAAGACCUACUACUUGACUCAGUUGAGCAUAUAUCGCAUCAGCCGGAUUGGUCCACAGAAAGGUUGUAAACCCACAGCGCUCUUAGAAGGUAAAAGGCAUUACCUUAUCCUAUCAAGACCACAUGUUCUAUUUGCCAACCGAACACUCUGCAAAAGCCGUAAGUCGAGCGCUUUGAGGGGAUCAGGGUGCUCCCUUGUCGACUAUGCGGCGGCGACGUUCAUCGUGGACUGGAGUCUCUAUCGAGUUGUCGAGCAUGAGGAGUUUUUUGUCCCUCUCAAGUUGUACGGCGUAGAUUGGUCGGUGGAUCAACUCCGUGUCACUCGCCCCCCCACAGAAGGGAUUCGGCAAGUGUGUUAUAUGGGAAAUGUACAAGAAGAUAUGUCAGUCGUCGACCUAUCUACAAAGAACCGUAGGCGUCGUGAAUCUUCUAACACGCGGCCAAGAAACGAAGAUCUCGUGGUUGUUCACUCUCCGGGCCUAACUACAGACAGUUCCGGACCUUGUCCUCAUUGUACGGUGAUACCGUCAUCGCACACUCACCGUUUUUCCGCGCCAGGGAGACCGGGCGAUUCGCGCACAGCAUAUGGCAAGGUGAGAUGUCUGUCUCACCGCCCUCGCAUCACUGACCCUAGCGUAUUCUCACCGAAAUCACGUCGUUGCUUAAGGCUAGGUCAUUCAUCCACGCGACGGGUACCAGCAAGUCCUCGCAGCGCUGCCGUGCCACACCAAACACGUGUGGACGUACCAAGGGGAGGCCAAAGGCAUCAGAGCGGUCGGUCCCUCGUUUACAUUUAUCAGAAUAAUCCAAACGCAAUGCUUCUUGCAGGCCAAUGGCGAUGCCCCGCGUAUGCCGCACUAUUGCAAGCCCCCUUUCCGUGGUGGAUAAGCUUGUCUUGUUGGUUACUCAAUGUAACUUCACAUCCAUUGCUUGCCGUUAUUAAUAGUACUUACCUGGGUGUCUUUUAUAUGACGCCUCGAAACCAGUCAAGUCGGGCAGGCGAGAGACUACGUAGAUAUCCAGUGGUUACUGCUGUGCUUCCCAGGUUAAUCUUGAUUGUUAUCCGAUUUUCAGACUUCUGCGCCGCAAAGUGGAAGAGUAAGUGGCUCUAUUCUGAUGGGUGUCAAUUGGCAGAAGCAAAAGAGGGCCACAGCGCCGAUCGUUCCCCAACAAGGUCGAUGUUCAAAGUGCAAAAGGCGGAUUUGGUCACUCUGGGAGAAAACGGCGCCGUAAGUCUUUGGUCAUUUGGGCCCAGUGGCAACCGGUACAUAACCACUGGCUAUCGUAUCAACGCGACUUGCACACGGGCUAGUAGUGAGAGUGCGCACCUCUCGAGGGUGGGCGGGCUUCUGAAGGGGUGUGAUAACUGUGAGCUUCCCUCAUGCUUGUACGUUCUCUUACCCUCUCUUUCUUUGUGUCAUCAAUUUCCCAGUGAAUGGCAUGAGCGCAUACAAUCCAAGUGGUUACGCACUCCCAAAACCCCGGAUGAACUAGAACCGCCGGAGCCUCAAAUUGGUGUGGGCAGCACGACGCGCCCACUAGAGAUUUGUACUUUUAUCCGGAAGCAUCGUAUAGGAACCGCAUUAUGGAUUGUGUUCCGUGAACCCUACCAGGUAGCACGGCUUAACUCGUGUUCCGCGCCCGAAGCUCUAAACGAGUUGCCACAUCCUCUCUUCAAACUUGAAAGUAUAUUAGAAGCAGCCCUGCAAACACGCUCAAGCACGGAACAGUAUCUUAUACGAAGUAGCGGAUACGGAGAUAUUCGAUCUGGCCACGCGAUUUCCAUCGGACCAGACCUGCAAAAUGUGGAAGUGGUGUCCGUAUGGUAUCUCCAACGACAGUGGCGCCACAAGAGGUCAGGCUCUCCGCUUAGACUGCAUUCUUCAUUUCUAUGGAAGAAUGGGUUGGCUUCUCCAGCGCAGUCACUUAUAACAGCCUCGUGUGAGGAAGCUAAGAGGUGUCCUCAUAAGCGGUCGCACCUAUUGGAUCUUAAGCUAUAUAAGUUGACCGCGAAGGCGGACUUGCCACCGUUACCAGCAUCGCAACCGAUUAUACCGCCUGUCGACGACGGGUACACCCAUGUCCCUUGUCGCUCUUAUCAGGGGCGUGGUCGAGGACGGAACGUAGCGGUUGGUCCCUUCCCCAGUACCGGAAACCCUACUCUGCAUCAGUCCGUUCACUCACACACUCGAUCUCACGUACUCCCAACCCAAGGAUGUUGGACGGGGUCUAAAGGCACUAUCGCUCCGGCUAUGCAGUUCAUAGGGUUGAGGCGUCAUCAUGCGUUCAGGGUGCACCAACACCCUAAAUCUUCUUACAGCCAUUGCGGUUCCUCGCUAGAGCCAGGGUACGUCGUAGGCGUGCCGAUAAUUGGGUCAGUCCUGGCCGCGGUUACUAGAGGGAAUGGAAGAGAGUAUAAAAAAGGUAAUGCCUGGUCGCGUUACCUCACGACCGAACGUUUGGCGGUGCGAAUAGCGAGGGAUUCAGGGGCUAUUCCCGUGGCGAGGGUAAGAGUUACACUUAACGGAGAGGAUCGAAUUCGGAUCCCCUUGGCCUUACGCGUGUAUGCCUUUCCGCCUGUCCCAUCAGCCAAGUUACCGUCCAAAACGGAAUCCACCUAUAGCUUUGCCAUGCGCUGUACUGACUGUUUGUGCGUAGUGAGCUUUACCGGAUCACUGUGGUGGAGGGCCCGACUAUCCAAGAGUGGCGACUAUUUCCUGCAUUCCCCUCAGAAUGCACGGUCGGGGACCUUGACCGGUCAUUCCCGCAUUCUGUGGGUUCUUACGUCUUUACGAAAUCCCCUCUUCACGGUCGUUCCCGGCCAAUUCAACAGUAUUAAAGGACGACCGACCGAGCACCUAUCAGGGGUAAGGUCUAGACCACUCCUGGAACUCGCACGCAAGACGCCAGGCCAAGGGAUUUUCUCAUUAGGCCCUUACGGCGGGCCCCAAUAUUUGAAUGCACUGAAAUCCUCAUUAGCCAGCAGACAACAUCUCACCGUUAACGCGGGGCAGGUGGGUGAUCGAGCUCUAACCUACGGUAUAGCUGAGUCGCACUCCAAAAGUAGCAGCAACUUUCAGUCGCUCCGGCGGCACGAACGGGAUGGCUCAAAAGACAUUCUUACACCGACGAGCGCAAAUUACAUUCGGAAGCCCACGUGCUGGCUAGUCGCGGGUAAGGUGUGCUAUUUUAGACAAACAAUUCUAGUCCCCGCAGUAAUGCGCACAUCGGCUGUGCGUCCACUAAAACAGAUCUCCUAUGAUCAUUAUUUUUGGGAGUGGAAAUGCUAUUAUAUAUGGCCAACUGGCCCCUGCUCUGUCCCUGACUGGGUACGGGAUGACUCCCCAACUCUGUGGAGAAUCGCUUUUCUAGCUUGCCUACGGAUCUGUUCAAGCGUUUUUCCCGUCAAUAUACGGGGACCCGAUAUAAUACAAAUCUGCAAGGGGUUUGAAAAAGGGCACAUGCAUCAAAAUCACGCGAAGCGCUCACUGAGCGCCAAUAACCGAAACCUAAGGAUACUCUCCGGCGCUGAAAGGCGGGCGAUGAUGGAUUCCCACAGUGGCCUAGCGAGGGUAAGGGCGUUGCGUCGACAUAUGGAAGGUGCGCGAUGCGACGUAAGGGGCGUAACUCAUGGGUCACAAUAUAGCUGCGGUAUACCUCAUCAACUAAUGGAACGGCGUACCUCAGAAUACUGCCUAACGCCGAAGGAGGCCUGCCUUAGUCGGUUCAUUAGAUUUGCCUUACCGGGGAGUCAUAUUCUGCAAGUUACUCCUGAGUUAGGGCCGGUCAUCGUCCCAGAUCAGAACUCUACGAGCAGCACAGGGGCCCUCCGGCCAGCCAACCCAAAUUGGAUCAAACUCGUUGGCGUCGUAGUUUACAAACCUGGAUGUGGAAUGCUCGUUUACUUGUCCGCAAGCGGACAGCAUAUCGGACCUGACAACCGAAACGGAACCAAGAACCGAGCUCAUCGCACACGGGUGUUCUCCUACCUGAUCCUAACUAUAACACGGCACCCGUCUGGACUGUGCUUUCAGGGGGACCCUAGGUCCAUCAAUUUGGCUGCCGACUGGAAGUCGGGUUCUGUGAUCAUCUCAUUGCAGUAUAGGUUCUCGACACGCUCUCCACUGUUAUCAUCAUAUCAGUUUCUUCAAGGCUCAACUCCCGUCAGAGCCGAUGUACUCAGAACCGGCAAGAGGACCUCGGGUGGGUUGUCUCCCAUCGAUCGGCUGGUCACGCCUGGGUCCGGUUGUCCGCCCCCUAUCCGUACGGACAUCCCCGAACGAGACACCGUCGCGUCGACGUCUGGUUUGGUUAUAAACAUUCCAUGUACAGCAUGUGCGACUCGAAGGACUGAUCAUUUGCGUAGUACCAAAAAGUGGGAGUCUGGGUGUUGCCCUGCUGGAAGCCCCCGUUAUCCCCGGUCUGAUAUUUCGUUGCCACGGAAUGUAGAAGUCCUGCAGUUGUGUAUUGCCAUCAAACUCAUUACCCACAAGGCUUGUAUAUGCUAUUUUCUGGCGCCUCUGGUUAGCCUGGAUACAAUUGCUCAAUCAAGGUAUGUUCCAUCGGAGUCGAAGACUCCUGAGGUAAUGUCCCACUCUGACGAUACCCACAGUUUCUCAUCUCUAGUAUCAAACGAAAUAUCCUCUACACUAAAAGCUUCUUACAAAGCAGGUGACUUAUCAUCAGUAGCCUGCUACAUACUGCCCUUAAACCCCAGUCUGAGUUCUGUUGAAGGCUGCACAACCUUCUGUCUAUCGGGGUUACUGCAAGGUGGGGUACACUCUGCAGGGGCACAUCAAGGUAGUAUACUAGAUCGGAUUAGUUCUUGGAGCAUUCAUUUUGCAAUGUGCAUCAAAUCCCUCUAUUGUCAGAUCCACAAGUUUAUAUUCAUGCACCCCGACGCUAAUAGGAAAAACCAAGGUUCUUUGAUCCCAGGUCAUGUUUGGGCGCGCGCUUGGGCCACAAAAUGCUGCAUCUGCUUCUGCGUCGGAGUGGACGGGACUAAUAGCAGGGAGGUGAGCUUGGGUCAAAUGCCUGCCAUGGAACCUAUUGCGUCGAGAGGAGCUACAUCAAGACGCAUAACUCUGUAUUGCAGCAAUGAAGUGAGUGACAUGACGGCGUUUUACUUCUCCGCGAGGAGUCUACCGGUAAUGAAAAACAGACCGCAACUAUGGAGGGAAUUAUGUAAGUCCCCCUCCGAGUUAUACGUAUGCCGGCUCUACGCCGGGGCUAUUCGUCGAAUUCGAAAUUUGGAAUACAACUCUUGUAAGAGGACCCGGAGCGAUUGCAAAGCGUAUGCCCGAGCGAGCAUAAUACGGUGUGCCCCGCUCCCAAUGGUGUAUUCUCACCUUCAGGCGGGGUGGAAUAAACUCUGUGGCCAUUGGAGGCGAGGAGUUUGUGCGGCGAACUGGUGCAUAUAUAGACCCCCCUUAUGCACGUGCACCAAGCCCUUGUGUACCAGGGCCGCUGAUCCAAAGAACAAGGACGAUAGCGGUCUUUCUUUUCUAGGUUACGUUCGGCCGUCCGAAGAAUCCACCUCGGCAGCAGGCAAAGUGCCUGGUACAAAGGUCCGACAUUGUCACUCAAGGCUAUCCACGGAUGAGCAGAUGACUGGCCUAACUGGCAUGCCGCUGCCCUGGUCUGAAGUACACUCCAGGAGUUUUCGUAGUCAUGUAGGGUGGCCCCAGUCAAGGGCUAUGCCGCUGCGACUCCCCCUCACUAGCGGCGAAGGUGGUCAUGUCUUAUCUACUCGCUCUGCCAGACCACAGAAUAGGCUUGGUAUUUCCCACGUCCCCGCGAUCUUACCACAUGUGUCCAAACAGGAAGUCCGUUCCAAGCAGUCAUUUGCUCGAGGGAUGGCUAAAAAAAUAGUCGGAGUUGGCGGGAAAGCUAACGCCCGGCAUUCACUCGCGUGCAUGCUGGAUUUACACCUUUGUGCGGUCUAUUGCGACAAAGCCGAUUCUUUGCUAAUCGCAAAGAAAGCCGAUGAACUAACGCAGUACAUCACAGGGCAAAGAAAGCCUGACUCCGUGAAGGCUUGUAGCGCAACAUCUAUCCUAGAUGAAAGACCGAUUAAAGCAUUACACAGCUACGGACACAGCGCGGUCCCUCGCAUACCCGCCUCCAACAUGUCCGCCGGCGCUUCUAGACACUUGGGCUCACCGUGCCGCAUUGCGUCUUCAAUUUUGAGUAGUCCAUUCUAUGCGAGAAAUUAUCUGAGGGUUGCCACUAACCCAUUCCAAGUGAGGUCCCGCUCCCUCAAAACACCAAUAUUCUCCAAUCCCCUUGAUACUAUGGGGCGACUUUGCCGGCAGAACCCACCCGUCUGCACUUCCGGGGAAGUAAUUAGUACGGAGGUUCGGAGCUCCUUCCUGGCGAUGCAUACUCUCAUUUCGCUCCAGCUCUCUCAACCGUUUCACUACGGGCAGAACAACGGUCACGAUGUAAAUGUGCCCCCAGCAUCUGAAGCACAUUUUACGCGCAGCGUAGAAUUCAGGACGUGGUGCCGCUUGCCCUGUGUAUUCAAUGAGGUAUUAAAGCAAAACUAUCAUUGUUUCGAUCAUUUACGCUCGCGCCUCUGGACUGAAGUCCGACACUGUGAGGCCAUCAACAUCCGGAUAUACUUUUAUCAUAUUAAGGGCACUCCCGUGCCGCGCUUACAUUAUCAUUCGAUUACCACCCUCUUUGAGACACAGAAAUUUGUGAGACUGCUCCCAUCCCUUUGCGGUCAUUUUUGUGCGAGCUUCGAGUUGCACAGUUAUUGUUUACGUUGCAGGUCCACCUGGAUUGUAGGUAAGAGUCGAGAGAUGGGGUUGAUGCGAGCCGCCCAUAACACAUCUUGCGGUGGCAUGCCCAUCCGAACGCAGUAUCGAGGGAGCGUUGUACUGCCAGGCCGGUCCGACAUGUGGAUUUUACACCUCUGCACUAUGCGGAAGAAUGAAGGCACCACCGGCUUCUUCUGGGCAUACUUUAUUCUAGUCUGUGGCAUAUGCUUUUCAUCCAUAGAAGCAACCCGCACAAUGAGAAGACGAGACCGCAGAAUACGUUUAAGGGUGUUAGCACUGAAGCCUUCGGAACUGGUAACUGAUAAGCUACACUCUCAAUCACCGACUUCAGAUCUGUCUUGUAAACAGAAUCCGAUAGAUCCUACAGCCCUGGCCUCCUUCAGGACUCGCGUCACCCUCCGUAAGGCCGCUGCAAGCUGCAUUAUGGGCCCCUUGGAGCAGGGAAGUAAGGCCCAGAUUGCCAGGUCCGUGCUUAUAAAAUUUGGUGGGCCUUUCAAGCAAUUAACGAUGUGUAACAUCUCGGCCAGUAGUAGGGACCAGUGCGCCGGACCCACGUACGCCUUAGUUGGGACUCAUGGAGAGGUGCAUGGACAUGUGCUUGUCAGACACGAGCAACCCAGACAUAUGUUCGCUUUUACUUUACUGUGGUCCCAUCGAGUAUACUUAGGAAGUCCUCGUCGUUUUUACAUGCUCUGCCGGCGCCGUGCGCCGCUAUCUUUUGUAGAACGCAGAGUACUGCAAACAGCAGUUGAGUACUCACCAACCGGCGCACUACUCUCAUGGUUGGGCCGGUCACUACUCUGGCUCCCACACACCGCUAUGGGUGUAGGGAAGCGAUUUGCCACAAACAGAGCGGAGACUUUAAUUCAUUCAGGGUAUCCCGCAGACCGAGUCCAGUCUGGCAAUGGUCAUAUUAGUAUUAGCGAUUCCAAUGGGUCCCUUGCGCCUAGUGGUAGGGAUUCUAAUCUAUCAUGCAAACGGUUUUCUACGCCUCCCUCGGUUUGCUUCGCCCUAUCAAGUUAUGGAACUGCAAGUUACAAAUUGACAAUAGCUCGACCCACAGUAAUCGCCGGCACUCCUAGAUCACUUGUAGCUAAAGGUAGUUACUUCAUCCCCAGGGCGUGGGAAGUCGGAACUGCGAUGGGAUGUAGAUCAACCUACUGCGAGGACGGAAGCUUCAAGGUUCGUCAACAUAUGGGUGAGCUGGCGUUCACGCCAAUGGCGUCGAAGCUUGCCCCGCGACUCCAUCAUUUGUAUCUAGGGAUCUCGACGUAG"What is the protein encoded? (the first 3 bps are a start codon and the last 3 are a stop codon)
protein = [] position = 0 while position < len(rna): protein.append(table[rna[position:position+3]]) position += 3 print (''.join(protein).replace('Stop', '')) - Use the below to perform the following tasks:
str1 = "GCAGTGTCCACGGGATGTAAACCCCGTTTGGGACCTGCCAGGCTTCCGCACTACAGTGTGTTGCGCGTACTAGACCTTATGCCCATATGAACCTAGCTCGGGCTACTTGGATCGAGGAACTCGATACTTCCCCTACTGCAGCCCAACAATATCGTAGAAGGCAATCGAATCGCCTAAAAATTTATCGCCGCATTTTACGTATATGCCGGCTGTGGCGTATAGCAGAAAACCGCTCCTCGCAAAGTCTGGAGTATTGGATGAACAGTACCCTGGATAGAGTTAAAGGGCCAGAAAAAGCCCAAGACCATGGCTTACCAAGTTCCGTCCTATTCAATATAACCTCAGGCAGCTATGCGGAACTTTCAATAAAATACCAAGACATGTCTCTGTCTGCTCCAGAGCGAGTGGATAGGCCCGATTATTTATGTGTCGGAGGACCATGGTTCGCAATTACACTCAAGCGAGCGATTTTTTAACTGTCCGTTCACCTCACGGACCTCGGGAGGATACAGAATCGGGTGGTAATATAACGAACATAACCGTTTGTGATCCTGGAAATACACAAGTTCATAAAAAGTGTGACCCGAAAGTGGTTTCACTATATAGGTATTCCCCCTAGTATGGCAATCTCGGTCAGTCAGCACTGGCCGATGGCTCAAGGCAACATTAGGGGTCGGCGAACGCAGTTGCTCCAAATACAAGTGTGGTTGCAAGTAGCATACGGCACACCGCGGTCTGGGTATGAGCCATACGTGTGATTTTGGTCAATTACCTAAGCAGCTTGTAGTCATAGCTATCTTACCGATTAGCGAACCCAATGAAGAGTTCCAGCATTCGCGAATGGGGGGTACAAGTAGGCTCTCGGCCGCCTACTAGACCGGGCGGTAAGGTGGCGTGTAGACCAAATCCTTA" str2 = "AACTAATCAAACTGGCTGGGATTCCTTCGGCTAAATACAGTCCCATCCAAGTATAGTCTGTTATTTGTGCTACGCCTCAAGCCTCTGATATGCGGTACCCTTGGATTTGGAGTGTAGGCCACCAGATCTGTTTTGATCCGGCCGGATCGTATCGAAAGATACTGAAGGAGCTCATAAACATTGAGCGTGTCAGAGTGGCCGAACGCCGGCGGTCGCTACAACAACAGGTCGTCGACTCCCTAACGCGCTGACATAGGTCTAATAGTCACGTGTATGGTTCTATCTGTGGAACAAAAACTAAAGCTCTTGGCTTAAGATGATCGTACCTGACGGATGTAAGATTCGACAACTAAACCGTTTTATCGTTAAAACATGCCGACCTGACTGTTGCTTCTACAGAGCGCGTTCAAAATCGTGCCTATCCTACAGTCGTACGCTGAGTGAACGCTCTTAAAATCTAGGAAGAGTAATCTTGCATATCCGAACCGAGCTTAGCCCTCCAATGAATAGAAGTACGCGCCTTTGTATTCCGAACATTTTCGTCTGCGATACTGGAAACATGTATGATCGTAAACACTGGGACCCGTCATTAGGTCTTTGATAGTATCGGTGCCTATATGGTGTCATTCTTATTCGGGCTAAACGAACGCTTGGCTCTGCGAATTGTAACCTGAGCTGAGGCGCACTCATAACACAACAAACGGAGCCTGGATATATCATAATGATTCTCCTGGGATGGGTACACGAGGCACCTTAGACTGCGCATTGCTCTAAGCACACCTAAGAGCCTGGTCAAGAACAGCTATTTGCGTACGCAAAGATGCGTTGATTCAATGGGGAACGCCGGGATCTTCTAGACTCGCAGCGCCCTCACTGCCGGGTGCGTAGCCTTGCGCCTGTCCATGATCACCA"- How many matches are there between the two strings?
- How many mismatches are there between the two strings?
- What is the GC content of the first string?
- What is the GC content of the second string?
sum([1 if x==y else 0 for x,y in zip(str1,str2)]) sum([1 if x!=y else 0 for x,y in zip(str1,str2)]) len(str1) - sum([1 if x==y else 0 for x,y in zip(str1,str2)]) # just to double check sum([1 if x=="G" or x=="C" else 0 for x in str1])/len(str1) sum([1 if x=="G" or x=="C" else 0 for x in str2])/len(str2) # OR by using count (str1.count("G")+str1.count("C"))/len(str1) (str1.count("G")+str1.count("C"))/len(str1)
- If you have any free time after these tasks take a moment to check out Rosalind. It is a great platform for continuing to challenge your python and bioinformatics!
